Author Topic: Pen Loses Connection Shortly After New Batteries  (Read 7788 times)

Offline ZMcElroy

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on: November 20, 2009, 11:04:16 PM
I got a basic pen from penteractive.us and got everything setup in the classroom. When I first got it all setup and calibrated it worked awesome for about 5 minutes. Then when I would hold down the button to draw a line it would skip and I would just get dots across the screen. I went and put new batteries in the pen and then it worked right away again for about 5 minutes after which the same problem arrived. I tried turning everything off and resetting up and still had the same problem. Once the initial 5 minutes of use are up it doesn't matter what I do it continues to jump around unless I put new batteries in.

Am i doing something wrong? I would imagine the batteries should last more than 5 minutes.

Thanks for the help.




Offline benpaddlejones

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Reply #1 on: November 21, 2009, 12:03:28 AM
ZMcElroy
penteractive.us uses a Vishay TSAL6400 so the IR-Led is not your issue, if you have used a new bettery then that won't be it either.

What screen utilisation are you getting?

Follow this for teh best setup guide: http://www.boonjin.com/smoothboard/index.php?title=Mount_and_position_the_Wiimote

Also make sure the batteries in your Wiimote are also 100%.

benpaddlejones :)


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Offline shakespeare1212

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Reply #2 on: November 21, 2009, 01:12:46 AM
Buy a pen with a resistor.  I'm just saying. If you don't limit the current in the circuit with a resistor, then yes your battery will be drained more quickly.

James Mclain
Owner and Creator of
Whalebone IR and Software

http://whaleboneir.com

or view and buy our products on ebay:

http://ebay.com   Search for IR pen or products by shakespeare1212.


Offline ZMcElroy

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Reply #3 on: November 21, 2009, 07:56:51 AM
I was getting around a 40% utilization. Also, the wiimote was at a 60% battery life. Shouldn't I be able to use it at that level or does it always have to be very close to 100%?

Thank you!



Offline jmitchell

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Reply #4 on: November 21, 2009, 02:55:14 PM
To ZMcElroy:

Before conclusions are drawn about the functionality of an item that has been purchased by 1000s of people and used very successfully, there are perhaps other questions that need to be raised.

1) What is the software being used to create the whiteboard (Smoothboard, Pentabulous, or WIWB for Mac) and on what platform (Windows XP, Vista...or Mac)?
2) How is the wiimote being positioned relative to the surface it is being focused upon?

Once we establish some basics on how you are using the pen, then we can progress further into why you are experiencing difficulties.

To shakespeare1212:

It is my understanding that a resistor only drops the amount of voltage being produced pushed through a component. Though certainly this means that an LED will last longer and not burn out as soon with a resistor in series, it does not guarantee longer battery life as the amount of current flowing out of the battery is constant when the circuit closed. The amount of voltage not used is given off as heat at the resistor if my rudimentary understanding of electronics is correct.

Wiimote Whiteboard Expert and seller - http://penteractive.us


Offline benpaddlejones

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Reply #5 on: November 22, 2009, 02:57:34 AM
The amount of voltage not used is given off as heat at the resistor if my rudimentary understanding of electronics is correct.

Correct, all a resitor does is protect the component.

I very much doubt its the IR-Pen (unless switch issue) using your mobile phone camera, click and hold the the switch and look at the IR-Led through the camera you will see the IR-Led illuminate if its bright and stabalily illuminated then IR-Pen is 100% (if not PM JMitchell and he'll sort it out for you).

Your next three challenges are surface, environment, and body position.
Surface
Use the IR-Pen as your righting if you see the number of detected IR Blog show 1,2 as your write then your surface is too reflective and is causing the irractic behaviour (very rare but does happen on some shinny whiteboards)
Environment
You might have some radiant IR-Light from the sun etc, look at the IR-Blob count in your IWB application if without using your IR-Pen you can see an Ir- count then your need to source the IR light and resolve
Body Position
Use my guide above to make sure the wiimote is correctly positioned. 40% is not bad but is on the low side unless a really big or small scrreen. What matter sthen is making sure your body or hand does not block the IR-Led. This requires you to maintain a open direct line of sight between the Wiimote and your IR-Led.

Let us know how you go...
benpaddlejones :)


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Offline boonjin

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Reply #6 on: November 22, 2009, 06:08:20 AM
It is my understanding that a resistor only drops the amount of voltage being produced pushed through a component. Though certainly this means that an LED will last longer and not burn out as soon with a resistor in series, it does not guarantee longer battery life as the amount of current flowing out of the battery is constant when the circuit closed. The amount of voltage not used is given off as heat at the resistor if my rudimentary understanding of electronics is correct.

Correct, all a resitor does is protect the component.

Hi Ben,

As a degree holder in Electrical and Electronic Engineering, I would like to clarify this issue regarding the existence of a resistor. This can be illustrated in a simply lay man scenario, if you connect the ends of a battery with a wire (low resistance), you will find that the battery will lose its power quickly. Therefore, the current flowing out from a battery is certainly not constant but depends on the circuit.

In high school physics, the common expression V=IR (Voltage = Current * Resistance), Ohm's law can be used. The larger the resistance, the smaller the current will pass through the resistor. Therefore, in the electrical circuit, the resistor is also called a current limiting resistor to control the current going through.

For a ordinary bulb, it acts as a resistor and thus the current going through the bulb follows the Ohm's law. However, the IR LED does not act like a resistor but is actually a diode. When the LED is working in the forward bias mode, there is a voltage drop called the forward voltage.

To calculate the optimum resistance for a specific IR LED, the following formula can be used
Resistance = (Supply Voltage - Voltage Drop (Forward Voltage)) / LED current rating according to specifications

Without a resistor, the current flowing through the diode will be quite large. As there is no external resistor present, we have to take into account the battery's internal resistance to be fed in the formula below. Usually with the presence of a resistor, the internal resistance is negligible.

Current = (Supply Voltage - Voltage Drop (Forward Voltage)) / Limiting Resistance

It can be seen that having a low resistance in the LED circuit will certainly have a large current flow through the LED. This will certainly cause a loss of power compared to using a resistor.

Hopefully this will benefit students who may be reading this forum.

Regards,
Boon Jin

Link:
http://www.vishay.com/docs/81011/tsal6400.pdf
« Last Edit: November 22, 2009, 08:06:11 AM by boonjin »

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