Wow, you guys are bright. I hope I'm not intruding too much but I think that this is a decent place to put in my two cents.
I was wanting to help teachers an implementers do a good job of placing the wii-remote to get the best tracking resolution. We are given the viewing angle of the Wii camera to be 45 degrees. So, I let Turbo Cad do my calculations, i.e. I drew an accurate sketch of a 45 degree angle at varrying distances from various screen sizes. Can one of you gentlemen work out the trigonometry and come up with a formula that translates a desired or given screen size into an optitmal distance that the Wiimote should be from the center of the screen, given that we will place on a normal coming straight out from the center of the screen. Are you with me?
Anyway here is a table of my results from Turbocad. Please someone tell me if I'm on the right track here. Do these numbers make sense?
Width of your screen Opitmal distance on a normal (straight out from the screen)
from left to right from the screen center for the Wiimote
32 inches 38.93 inches
52 inches 62.78 inches
102 inches 123.185 inches
200 inches 240.3469 inches
This data was just based on the demsion tools in TurboCad. I would be happy to email my turbo cad file ( or a JPEG) to anyone who is interested, but I would prefer to use trig. and develop a simple formula.
OK,... I thought a little harder about it....
The formula I have is: Optimal distance from the screen = (Sceen width (left to right) / 2)/ tan 22.5 degrees.
Bam!! I check it against the table. It works!!